Base | Representation |
---|---|
bin | 10010110001001001… |
… | …111110110110010011 |
3 | 1221000102122100221111 |
4 | 102301021332312103 |
5 | 312232411200024 |
6 | 13131400234151 |
7 | 1312246424341 |
oct | 226111766623 |
9 | 57012570844 |
10 | 20152053139 |
11 | 8601343879 |
12 | 3aa4a6b957 |
13 | 1b920451ca |
14 | d92586991 |
15 | 7ce2a3a94 |
hex | 4b127ed93 |
20152053139 has 2 divisors, whose sum is σ = 20152053140. Its totient is φ = 20152053138.
The previous prime is 20152053133. The next prime is 20152053149. The reversal of 20152053139 is 93135025102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20152053139 - 211 = 20152051091 is a prime.
It is a super-2 number, since 2×201520531392 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20152053139.
It is not a weakly prime, because it can be changed into another prime (20152053133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076026569 + 10076026570.
It is an arithmetic number, because the mean of its divisors is an integer number (10076026570).
Almost surely, 220152053139 is an apocalyptic number.
20152053139 is a deficient number, since it is larger than the sum of its proper divisors (1).
20152053139 is an equidigital number, since it uses as much as digits as its factorization.
20152053139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 31.
The spelling of 20152053139 in words is "twenty billion, one hundred fifty-two million, fifty-three thousand, one hundred thirty-nine".
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