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201521113 is a prime number
BaseRepresentation
bin11000000001011…
…11011111011001
3112001012022222221
430000233133121
5403042133423
631555144041
74664621053
oct1400573731
9461168887
10201521113
11a3831882
12575a5021
133299a781
141ca9a8d3
1512a59e5d
hexc02f7d9

201521113 has 2 divisors, whose sum is σ = 201521114. Its totient is φ = 201521112.

The previous prime is 201521093. The next prime is 201521141. The reversal of 201521113 is 311125102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195105024 + 6416089 = 13968^2 + 2533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201521113 is a prime.

It is a super-2 number, since 2×2015211132 = 81221517969517538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201521413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100760556 + 100760557.

It is an arithmetic number, because the mean of its divisors is an integer number (100760557).

Almost surely, 2201521113 is an apocalyptic number.

It is an amenable number.

201521113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201521113 is an equidigital number, since it uses as much as digits as its factorization.

201521113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 201521113 is about 14195.8132208056. The cubic root of 201521113 is about 586.2823919376.

Adding to 201521113 its reverse (311125102), we get a palindrome (512646215).

The spelling of 201521113 in words is "two hundred one million, five hundred twenty-one thousand, one hundred thirteen".