Base | Representation |
---|---|
bin | 10010110001001010… |
… | …010111100101000001 |
3 | 1221000102211111220010 |
4 | 102301022113211001 |
5 | 312232422420213 |
6 | 13131402335133 |
7 | 1312250325555 |
oct | 226112274501 |
9 | 57012744803 |
10 | 20152154433 |
11 | 8601402994 |
12 | 3aa4aba4a9 |
13 | 1b9207c348 |
14 | d925b1865 |
15 | 7ce2c3ac3 |
hex | 4b1297941 |
20152154433 has 32 divisors (see below), whose sum is σ = 30980188800. Its totient is φ = 11565904896.
The previous prime is 20152154423. The next prime is 20152154443. The reversal of 20152154433 is 33445125102.
It is an interprime number because it is at equal distance from previous prime (20152154423) and next prime (20152154443).
It is not a de Polignac number, because 20152154433 - 213 = 20152146241 is a prime.
It is a super-2 number, since 2×201521544332 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20152154433.
It is not an unprimeable number, because it can be changed into a prime (20152154413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 330466 + ... + 386667.
It is an arithmetic number, because the mean of its divisors is an integer number (968130900).
Almost surely, 220152154433 is an apocalyptic number.
It is an amenable number.
20152154433 is a deficient number, since it is larger than the sum of its proper divisors (10828034367).
20152154433 is a wasteful number, since it uses less digits than its factorization.
20152154433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 717201.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 20152154433 its reverse (33445125102), we get a palindrome (53597279535).
The spelling of 20152154433 in words is "twenty billion, one hundred fifty-two million, one hundred fifty-four thousand, four hundred thirty-three".
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