2015250434513 has 2 divisors, whose sum is σ = 2015250434514. Its totient is φ = 2015250434512.

The previous prime is 2015250434419. The next prime is 2015250434531. The reversal of 2015250434513 is 3154340525102.

Together with next prime (2015250434531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1788914275009 + 226336159504 = 1337503^2 + 475748^2 .

It is a cyclic number.

It is not a de Polignac number, because 2015250434513 - 2²² = 2015246240209 is a prime.

It is a super-2 number, since 2×2015250434513² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2015250494513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007625217256 + 1007625217257.

It is an arithmetic number, because the mean of its divisors is an integer number (1007625217257).

Almost surely, 2^{2015250434513} is an apocalyptic number.

It is an amenable number.

2015250434513 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015250434513 is an equidigital number, since it uses as much as digits as its factorization.

2015250434513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 2015250434513 its reverse (3154340525102), we get a palindrome (5169590959615).

The spelling of 2015250434513 in words is "two trillion, fifteen billion, two hundred fifty million, four hundred thirty-four thousand, five hundred thirteen".