Base | Representation |
---|---|
bin | 101101110100101010010111… |
… | …101011000110001110111011 |
3 | 222102120011201220110110201212 |
4 | 231310222113223012032323 |
5 | 202403340442012322001 |
6 | 1552342021403233335 |
7 | 60310064024523434 |
oct | 5564522753061673 |
9 | 872504656413655 |
10 | 201531000120251 |
11 | 592398a973592a |
12 | 1a72a08421884b |
13 | 885b3a401a3b9 |
14 | 37aa21c47848b |
15 | 184743cc697bb |
hex | b74a97ac63bb |
201531000120251 has 32 divisors (see below), whose sum is σ = 207677956147200. Its totient is φ = 195456184197120.
The previous prime is 201531000120239. The next prime is 201531000120313. The reversal of 201531000120251 is 152021000135102.
It is a cyclic number.
It is not a de Polignac number, because 201531000120251 - 222 = 201530995925947 is a prime.
It is a super-2 number, since 2×2015310001202512 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (201531000120851) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4981096460 + ... + 4981136918.
It is an arithmetic number, because the mean of its divisors is an integer number (6489936129600).
Almost surely, 2201531000120251 is an apocalyptic number.
201531000120251 is a deficient number, since it is larger than the sum of its proper divisors (6146956026949).
201531000120251 is a wasteful number, since it uses less digits than its factorization.
201531000120251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42179.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 201531000120251 its reverse (152021000135102), we get a palindrome (353552000255353).
The spelling of 201531000120251 in words is "two hundred one trillion, five hundred thirty-one billion, one hundred twenty thousand, two hundred fifty-one".
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