Search a number
-
+
201531000120313 is a prime number
BaseRepresentation
bin101101110100101010010111…
…101011000110001111111001
3222102120011201220110110211011
4231310222113223012033321
5202403340442012322223
61552342021403233521
760310064024523553
oct5564522753061771
9872504656413734
10201531000120313
11592398a9735986
121a72a0842188a1
13885b3a401a436
1437aa21c4784d3
15184743cc6980d
hexb74a97ac63f9

201531000120313 has 2 divisors, whose sum is σ = 201531000120314. Its totient is φ = 201531000120312.

The previous prime is 201531000120239. The next prime is 201531000120323. The reversal of 201531000120313 is 313021000135102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143108870947344 + 58422129172969 = 11962812^2 + 7643437^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201531000120313 is a prime.

It is a super-2 number, since 2×2015310001203132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201531000120323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100765500060156 + 100765500060157.

It is an arithmetic number, because the mean of its divisors is an integer number (100765500060157).

Almost surely, 2201531000120313 is an apocalyptic number.

It is an amenable number.

201531000120313 is a deficient number, since it is larger than the sum of its proper divisors (1).

201531000120313 is an equidigital number, since it uses as much as digits as its factorization.

201531000120313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 201531000120313 its reverse (313021000135102), we get a palindrome (514552000255415).

The spelling of 201531000120313 in words is "two hundred one trillion, five hundred thirty-one billion, one hundred twenty thousand, three hundred thirteen".