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20153143463 = 127158686169
BaseRepresentation
bin10010110001001110…
…001001000010100111
31221000111200202120212
4102301032021002213
5312233201042323
613131435450035
71312261615205
oct226116110247
957014622525
1020153143463
118601a18a72
123aa52b691b
131b9233757b
14d9278c075
157ce41bb78
hex4b13890a7

20153143463 has 4 divisors (see below), whose sum is σ = 20311829760. Its totient is φ = 19994457168.

The previous prime is 20153143457. The next prime is 20153143487. The reversal of 20153143463 is 36434135102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20153143463 - 212 = 20153139367 is a prime.

It is a super-2 number, since 2×201531434632 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20153143163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79342958 + ... + 79343211.

It is an arithmetic number, because the mean of its divisors is an integer number (5077957440).

Almost surely, 220153143463 is an apocalyptic number.

20153143463 is a deficient number, since it is larger than the sum of its proper divisors (158686297).

20153143463 is a wasteful number, since it uses less digits than its factorization.

20153143463 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158686296.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 20153143463 its reverse (36434135102), we get a palindrome (56587278565).

The spelling of 20153143463 in words is "twenty billion, one hundred fifty-three million, one hundred forty-three thousand, four hundred sixty-three".

Divisors: 1 127 158686169 20153143463