Base | Representation |
---|---|
bin | 1001001010100010010011… |
… | …10010100001100001110111 |
3 | 2122100121222212110022210111 |
4 | 10211101021302201201313 |
5 | 10120142300440043020 |
6 | 110510132531403451 |
7 | 4150010456045200 |
oct | 445211162414167 |
9 | 78317885408714 |
10 | 20153224534135 |
11 | 646aa30946430 |
12 | 23159b6153587 |
13 | b32596911b54 |
14 | 4d95c7d825a7 |
15 | 24e371aacd5a |
hex | 125449ca1877 |
20153224534135 has 48 divisors (see below), whose sum is σ = 30692483956512. Its totient is φ = 12561923404800.
The previous prime is 20153224534081. The next prime is 20153224534139. The reversal of 20153224534135 is 53143542235102.
It is not a de Polignac number, because 20153224534135 - 213 = 20153224525943 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20153224534139) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 30266995 + ... + 30925675.
It is an arithmetic number, because the mean of its divisors is an integer number (639426749094).
Almost surely, 220153224534135 is an apocalyptic number.
20153224534135 is a deficient number, since it is larger than the sum of its proper divisors (10539259422377).
20153224534135 is a wasteful number, since it uses less digits than its factorization.
20153224534135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670064 (or 670057 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 20153224534135 its reverse (53143542235102), we get a palindrome (73296766769237).
The spelling of 20153224534135 in words is "twenty trillion, one hundred fifty-three billion, two hundred twenty-four million, five hundred thirty-four thousand, one hundred thirty-five".
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