201541230334341 has 10 divisors (see below), whose sum is σ = 301067763832902. Its totient is φ = 134360820222840.

The previous prime is 201541230334333. The next prime is 201541230334387. The reversal of 201541230334341 is 143433032145102.

201541230334341 is a `hidden beast` number, since 2 + 0 + 1 + 5 + 4 + 1 + 2 + 303 + 3 + 4 + 341 = 666.

201541230334341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 181987411653441 + 19553818680900 = 13490271^2 + 4421970^2 .

It is not a de Polignac number, because 201541230334341 - 2³ = 201541230334333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201541230334296 and 201541230334305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201541230334321) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 1244081668650 + ... + 1244081668811.

Almost surely, 2^{201541230334341} is an apocalyptic number.

It is an amenable number.

201541230334341 is a deficient number, since it is larger than the sum of its proper divisors (99526533498561).

201541230334341 is an equidigital number, since it uses as much as digits as its factorization.

201541230334341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2488163337473 (or 2488163337464 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 36.

Adding to 201541230334341 its reverse (143433032145102), we get a palindrome (344974262479443).

The spelling of 201541230334341 in words is "two hundred one trillion, five hundred forty-one billion, two hundred thirty million, three hundred thirty-four thousand, three hundred forty-one".