201541425493 has 4 divisors (see below), whose sum is σ = 212148868960. Its totient is φ = 190933982028.

The previous prime is 201541425451. The next prime is 201541425497. The reversal of 201541425493 is 394524145102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 394524145102 = 2 ⋅197262072551.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201541425493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201541425497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303721705 + ... + 5303721742.

It is an arithmetic number, because the mean of its divisors is an integer number (53037217240).

Almost surely, 2^201541425493 is an apocalyptic number.

It is an amenable number.

201541425493 is a deficient number, since it is larger than the sum of its proper divisors (10607443467).

201541425493 is a wasteful number, since it uses less digits than its factorization.

201541425493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10607443466.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 201541425493 in words is "two hundred one billion, five hundred forty-one million, four hundred twenty-five thousand, four hundred ninety-three".