20155340141401 has 2 divisors, whose sum is σ = 20155340141402. Its totient is φ = 20155340141400.

The previous prime is 20155340141389. The next prime is 20155340141471. The reversal of 20155340141401 is 10414104355102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19113509610000 + 1041830531401 = 4371900^2 + 1020701^2 .

It is a cyclic number.

It is not a de Polignac number, because 20155340141401 - 2⁵ = 20155340141369 is a prime.

It is not a weakly prime, because it can be changed into another prime (20155340141471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077670070700 + 10077670070701.

It is an arithmetic number, because the mean of its divisors is an integer number (10077670070701).

Almost surely, 2^{20155340141401} is an apocalyptic number.

It is an amenable number.

20155340141401 is a deficient number, since it is larger than the sum of its proper divisors (1).

20155340141401 is an equidigital number, since it uses as much as digits as its factorization.

20155340141401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 20155340141401 its reverse (10414104355102), we get a palindrome (30569444496503).

The spelling of 20155340141401 in words is "twenty trillion, one hundred fifty-five billion, three hundred forty million, one hundred forty-one thousand, four hundred one".