20155340141437 has 4 divisors (see below), whose sum is σ = 20805512404096. Its totient is φ = 19505167878780.

The previous prime is 20155340141401. The next prime is 20155340141471. The reversal of 20155340141437 is 73414104355102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20155340141437 - 2³¹ = 20153192657789 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20155340141437.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20155340141537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325086131283 + ... + 325086131344.

It is an arithmetic number, because the mean of its divisors is an integer number (5201378101024).

Almost surely, 2^{20155340141437} is an apocalyptic number.

It is an amenable number.

20155340141437 is a deficient number, since it is larger than the sum of its proper divisors (650172262659).

20155340141437 is an equidigital number, since it uses as much as digits as its factorization.

20155340141437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 650172262658.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 20155340141437 its reverse (73414104355102), we get a palindrome (93569444496539).

The spelling of 20155340141437 in words is "twenty trillion, one hundred fifty-five billion, three hundred forty million, one hundred forty-one thousand, four hundred thirty-seven".