Base | Representation |
---|---|
bin | 1001001010100110011000… |
… | …10010101100010110011111 |
3 | 2122100211122110022222101121 |
4 | 10211103030102230112133 |
5 | 10120211241441131101 |
6 | 110511134103351411 |
7 | 4150115643202465 |
oct | 445231422542637 |
9 | 78324573288347 |
10 | 20155414005151 |
11 | 6470954834407 |
12 | 2316307452567 |
13 | b328553c7c29 |
14 | 4d9754a7c835 |
15 | 24e44ddea0a1 |
hex | 1254cc4ac59f |
20155414005151 has 4 divisors (see below), whose sum is σ = 21216225268600. Its totient is φ = 19094602741704.
The previous prime is 20155414005149. The next prime is 20155414005193. The reversal of 20155414005151 is 15150041455102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20155414005151 - 21 = 20155414005149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20155414005121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530405631696 + ... + 530405631733.
It is an arithmetic number, because the mean of its divisors is an integer number (5304056317150).
Almost surely, 220155414005151 is an apocalyptic number.
20155414005151 is a deficient number, since it is larger than the sum of its proper divisors (1060811263449).
20155414005151 is a wasteful number, since it uses less digits than its factorization.
20155414005151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060811263448.
The product of its (nonzero) digits is 20000, while the sum is 34.
The spelling of 20155414005151 in words is "twenty trillion, one hundred fifty-five billion, four hundred fourteen million, five thousand, one hundred fifty-one".
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