2016122113 has 2 divisors, whose sum is σ = 2016122114. Its totient is φ = 2016122112.

The previous prime is 2016122057. The next prime is 2016122131. The reversal of 2016122113 is 3112216102.

Together with next prime (2016122131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1203187969 + 812934144 = 34687^2 + 28512^2 .

It is a cyclic number.

It is not a de Polignac number, because 2016122113 - 2¹⁷ = 2015991041 is a prime.

It is not a weakly prime, because it can be changed into another prime (2016102113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008061056 + 1008061057.

It is an arithmetic number, because the mean of its divisors is an integer number (1008061057).

Almost surely, 2^2016122113 is an apocalyptic number.

It is an amenable number.

2016122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2016122113 is an equidigital number, since it uses as much as digits as its factorization.

2016122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 2016122113 is about 44901.2484570307. The cubic root of 2016122113 is about 1263.2974252868.

Adding to 2016122113 its reverse (3112216102), we get a palindrome (5128338215).

The spelling of 2016122113 in words is "two billion, sixteen million, one hundred twenty-two thousand, one hundred thirteen".