Base | Representation |
---|---|
bin | 11101010101101011001… |
… | …110111000010001011001 |
3 | 21010202000011200222220221 |
4 | 131111223032320101121 |
5 | 231013023003140231 |
6 | 4142111253520041 |
7 | 265442540253562 |
oct | 35255316702131 |
9 | 7122004628827 |
10 | 2016138724441 |
11 | 708048827386 |
12 | 2868a8943021 |
13 | 118175c9c16a |
14 | 6d820013169 |
15 | 3769ec76d11 |
hex | 1d56b3b8459 |
2016138724441 has 2 divisors, whose sum is σ = 2016138724442. Its totient is φ = 2016138724440.
The previous prime is 2016138724427. The next prime is 2016138724477. The reversal of 2016138724441 is 1444278316102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1681703208025 + 334435516416 = 1296805^2 + 578304^2 .
It is a cyclic number.
It is not a de Polignac number, because 2016138724441 - 25 = 2016138724409 is a prime.
It is not a weakly prime, because it can be changed into another prime (2016138724241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008069362220 + 1008069362221.
It is an arithmetic number, because the mean of its divisors is an integer number (1008069362221).
Almost surely, 22016138724441 is an apocalyptic number.
It is an amenable number.
2016138724441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2016138724441 is an equidigital number, since it uses as much as digits as its factorization.
2016138724441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 43.
The spelling of 2016138724441 in words is "two trillion, sixteen billion, one hundred thirty-eight million, seven hundred twenty-four thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •