Base | Representation |
---|---|
bin | 11101010101111100110… |
… | …010111110110110101011 |
3 | 21010202202201012010112011 |
4 | 131111330302332312223 |
5 | 231014123422320014 |
6 | 4142200421500351 |
7 | 265453046052634 |
oct | 35257462766653 |
9 | 7122681163464 |
10 | 2016433401259 |
11 | 70818a0a5442 |
12 | 28696b5716b7 |
13 | 1181c2055044 |
14 | 6d84b1dc88b |
15 | 376baa837c4 |
hex | 1d57ccbedab |
2016433401259 has 2 divisors, whose sum is σ = 2016433401260. Its totient is φ = 2016433401258.
The previous prime is 2016433401253. The next prime is 2016433401271. The reversal of 2016433401259 is 9521043346102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2016433401259 - 23 = 2016433401251 is a prime.
It is not a weakly prime, because it can be changed into another prime (2016433401251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008216700629 + 1008216700630.
It is an arithmetic number, because the mean of its divisors is an integer number (1008216700630).
Almost surely, 22016433401259 is an apocalyptic number.
2016433401259 is a deficient number, since it is larger than the sum of its proper divisors (1).
2016433401259 is an equidigital number, since it uses as much as digits as its factorization.
2016433401259 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 2016433401259 in words is "two trillion, sixteen billion, four hundred thirty-three million, four hundred one thousand, two hundred fifty-nine".
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