Base | Representation |
---|---|
bin | 11101010110000011111… |
… | …111011010101001011101 |
3 | 21010210002010022022220120 |
4 | 131112003333122221131 |
5 | 231014400322220331 |
6 | 4142220412505153 |
7 | 265456043021133 |
oct | 35260377325135 |
9 | 7123063268816 |
10 | 2016554101341 |
11 | 70824124517a |
12 | 2869a3a7b1b9 |
13 | 118211065800 |
14 | 6d85d25b753 |
15 | 376c6476796 |
hex | 1d583fdaa5d |
2016554101341 has 48 divisors (see below), whose sum is σ = 2925379440000. Its totient is φ = 1235038371840.
The previous prime is 2016554101327. The next prime is 2016554101351. The reversal of 2016554101341 is 1431014556102.
It is not a de Polignac number, because 2016554101341 - 29 = 2016554100829 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2016554101351) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 162737256 + ... + 162749646.
It is an arithmetic number, because the mean of its divisors is an integer number (60945405000).
Almost surely, 22016554101341 is an apocalyptic number.
It is an amenable number.
2016554101341 is a deficient number, since it is larger than the sum of its proper divisors (908825338659).
2016554101341 is a wasteful number, since it uses less digits than its factorization.
2016554101341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13926 (or 13913 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 2016554101341 its reverse (1431014556102), we get a palindrome (3447568657443).
The spelling of 2016554101341 in words is "two trillion, sixteen billion, five hundred fifty-four million, one hundred one thousand, three hundred forty-one".
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