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20175395759993 is a prime number
BaseRepresentation
bin1001001011001011100110…
…10011000010011101111001
32122102202020000112021222202
410211211303103002131321
510121023202303304433
6110524240541555545
74151424054256505
oct445456323023571
978382200467882
1020175395759993
116479378a31591
12231a163275bb5
13b346bb0850c6
144da6cc775305
1524ec1d25eee8
hex1259734c2779

20175395759993 has 2 divisors, whose sum is σ = 20175395759994. Its totient is φ = 20175395759992.

The previous prime is 20175395759989. The next prime is 20175395760029. The reversal of 20175395759993 is 39995759357102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20150016721129 + 25379038864 = 4488877^2 + 159308^2 .

It is a cyclic number.

It is not a de Polignac number, because 20175395759993 - 22 = 20175395759989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20175395759993.

It is not a weakly prime, because it can be changed into another prime (20175395759593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10087697879996 + 10087697879997.

It is an arithmetic number, because the mean of its divisors is an integer number (10087697879997).

Almost surely, 220175395759993 is an apocalyptic number.

It is an amenable number.

20175395759993 is a deficient number, since it is larger than the sum of its proper divisors (1).

20175395759993 is an equidigital number, since it uses as much as digits as its factorization.

20175395759993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 723350250, while the sum is 74.

The spelling of 20175395759993 in words is "twenty trillion, one hundred seventy-five billion, three hundred ninety-five million, seven hundred fifty-nine thousand, nine hundred ninety-three".