201761120993 has 2 divisors, whose sum is σ = 201761120994. Its totient is φ = 201761120992.

The previous prime is 201761120987. The next prime is 201761121017. The reversal of 201761120993 is 399021167102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146530480849 + 55230640144 = 382793^2 + 235012^2 .

It is a cyclic number.

It is not a de Polignac number, because 201761120993 - 2¹⁰ = 201761119969 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 201761120993.

It is not a weakly prime, because it can be changed into another prime (201761120923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100880560496 + 100880560497.

It is an arithmetic number, because the mean of its divisors is an integer number (100880560497).

Almost surely, 2^201761120993 is an apocalyptic number.

It is an amenable number.

201761120993 is a deficient number, since it is larger than the sum of its proper divisors (1).

201761120993 is an equidigital number, since it uses as much as digits as its factorization.

201761120993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 201761120993 in words is "two hundred one billion, seven hundred sixty-one million, one hundred twenty thousand, nine hundred ninety-three".