Search a number
-
+
20181253 = 71284243
BaseRepresentation
bin100110011111…
…1000100000101
31101222022110211
41030333010011
520131300003
62000315421
7333352321
oct114770405
941868424
1020181253
1110434524
126912b71
134247a91
142974981
151b8996d
hex133f105

20181253 has 4 divisors (see below), whose sum is σ = 20465568. Its totient is φ = 19896940.

The previous prime is 20181247. The next prime is 20181311. The reversal of 20181253 is 35218102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35218102 = 217609051.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20181253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20181223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142051 + ... + 142192.

It is an arithmetic number, because the mean of its divisors is an integer number (5116392).

Almost surely, 220181253 is an apocalyptic number.

It is an amenable number.

20181253 is a deficient number, since it is larger than the sum of its proper divisors (284315).

20181253 is an equidigital number, since it uses as much as digits as its factorization.

20181253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 284314.

The product of its (nonzero) digits is 480, while the sum is 22.

The square root of 20181253 is about 4492.3549503573. The cubic root of 20181253 is about 272.2592908443.

Adding to 20181253 its reverse (35218102), we get a palindrome (55399355).

The spelling of 20181253 in words is "twenty million, one hundred eighty-one thousand, two hundred fifty-three".

Divisors: 1 71 284243 20181253