Base | Representation |
---|---|
bin | 1001001011011000110111… |
… | …01110111100001111110011 |
3 | 2122110102121021200011111012 |
4 | 10211230123232330033303 |
5 | 10121132243223123011 |
6 | 110531415314341135 |
7 | 4152065401445264 |
oct | 445543356741763 |
9 | 78412537604435 |
10 | 20182516614131 |
11 | 64813a2520703 |
12 | 231b60bb8a7ab |
13 | b35284423971 |
14 | 4daba639096b |
15 | 24eed849ca8b |
hex | 125b1bbbc3f3 |
20182516614131 has 2 divisors, whose sum is σ = 20182516614132. Its totient is φ = 20182516614130.
The previous prime is 20182516614121. The next prime is 20182516614173. The reversal of 20182516614131 is 13141661528102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20182516614131 - 242 = 15784470103027 is a prime.
It is a super-2 number, since 2×201825166141312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20182516614121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10091258307065 + 10091258307066.
It is an arithmetic number, because the mean of its divisors is an integer number (10091258307066).
Almost surely, 220182516614131 is an apocalyptic number.
20182516614131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20182516614131 is an equidigital number, since it uses as much as digits as its factorization.
20182516614131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 41.
The spelling of 20182516614131 in words is "twenty trillion, one hundred eighty-two billion, five hundred sixteen million, six hundred fourteen thousand, one hundred thirty-one".
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