Base | Representation |
---|---|
bin | 11101010111110001001… |
… | …010010100000011110011 |
3 | 21010221210202201212220212 |
4 | 131113301022110003303 |
5 | 231032123213040413 |
6 | 4143122241454335 |
7 | 265552323105413 |
oct | 35276112240363 |
9 | 7127722655825 |
10 | 2018385674483 |
11 | 708aa1104192 |
12 | 2872153413ab |
13 | 11844365b8b9 |
14 | 6d9945d2643 |
15 | 37782169ca8 |
hex | 1d5f12940f3 |
2018385674483 has 2 divisors, whose sum is σ = 2018385674484. Its totient is φ = 2018385674482.
The previous prime is 2018385674467. The next prime is 2018385674593. The reversal of 2018385674483 is 3844765838102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2018385674483 - 24 = 2018385674467 is a prime.
It is not a weakly prime, because it can be changed into another prime (2018385674983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1009192837241 + 1009192837242.
It is an arithmetic number, because the mean of its divisors is an integer number (1009192837242).
Almost surely, 22018385674483 is an apocalyptic number.
2018385674483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2018385674483 is an equidigital number, since it uses as much as digits as its factorization.
2018385674483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30965760, while the sum is 59.
The spelling of 2018385674483 in words is "two trillion, eighteen billion, three hundred eighty-five million, six hundred seventy-four thousand, four hundred eighty-three".
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