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20201220120111 = 36733740040037
BaseRepresentation
bin1001001011111011101101…
…00011001001111000101111
32122112012212202121201021220
410211331312203021320233
510121434044322320421
6110544151251354423
74153330031563242
oct445756643117057
978465782551256
1020201220120111
116489320127568
12232316b8b2a13
13b36c75320374
144dba5c3c9259
152507304bc3c6
hex125f768c9e2f

20201220120111 has 4 divisors (see below), whose sum is σ = 26934960160152. Its totient is φ = 13467480080072.

The previous prime is 20201220120101. The next prime is 20201220120119. The reversal of 20201220120111 is 11102102210202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20201220120111 - 29 = 20201220119599 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20201220120119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3366870020016 + ... + 3366870020021.

It is an arithmetic number, because the mean of its divisors is an integer number (6733740040038).

Almost surely, 220201220120111 is an apocalyptic number.

20201220120111 is a deficient number, since it is larger than the sum of its proper divisors (6733740040041).

20201220120111 is an equidigital number, since it uses as much as digits as its factorization.

20201220120111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6733740040040.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 20201220120111 its reverse (11102102210202), we get a palindrome (31303322330313).

The spelling of 20201220120111 in words is "twenty trillion, two hundred one billion, two hundred twenty million, one hundred twenty thousand, one hundred eleven".

Divisors: 1 3 6733740040037 20201220120111