Base | Representation |
---|---|
bin | 1001001011111011101111… |
… | …10011100100101111000001 |
3 | 2122112012221020021202122211 |
4 | 10211331313303210233001 |
5 | 10121434120221422401 |
6 | 110544153323302121 |
7 | 4153330406015305 |
oct | 445756763445701 |
9 | 78465836252584 |
10 | 20201241201601 |
11 | 6489331016389 |
12 | 232317697a941 |
13 | b36c797c1b15 |
14 | 4dba61115d05 |
15 | 250732283951 |
hex | 125f77ce4bc1 |
20201241201601 has 2 divisors, whose sum is σ = 20201241201602. Its totient is φ = 20201241201600.
The previous prime is 20201241201593. The next prime is 20201241201607. The reversal of 20201241201601 is 10610214210202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10654995111601 + 9546246090000 = 3264199^2 + 3089700^2 .
It is a cyclic number.
It is not a de Polignac number, because 20201241201601 - 23 = 20201241201593 is a prime.
It is not a weakly prime, because it can be changed into another prime (20201241201607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10100620600800 + 10100620600801.
It is an arithmetic number, because the mean of its divisors is an integer number (10100620600801).
Almost surely, 220201241201601 is an apocalyptic number.
It is an amenable number.
20201241201601 is a deficient number, since it is larger than the sum of its proper divisors (1).
20201241201601 is an equidigital number, since it uses as much as digits as its factorization.
20201241201601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 20201241201601 its reverse (10610214210202), we get a palindrome (30811455411803).
The spelling of 20201241201601 in words is "twenty trillion, two hundred one billion, two hundred forty-one million, two hundred one thousand, six hundred one".
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