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20201343424114 = 210100671712057
BaseRepresentation
bin1001001011111011111011…
…11001100001011001110010
32122112020012100122012120211
410211331331321201121302
510121434322404032424
6110544211414254334
74153333056625156
oct445757571413162
978466170565524
1020201343424114
1164893837956a6
1223231a50573aa
13b36c94a33108
144dba70925066
1525073b226b94
hex125f7de61672

20201343424114 has 4 divisors (see below), whose sum is σ = 30302015136174. Its totient is φ = 10100671712056.

The previous prime is 20201343424091. The next prime is 20201343424117. The reversal of 20201343424114 is 41142434310202.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 18725810892889 + 1475532531225 = 4327333^2 + 1214715^2 .

It is a super-2 number, since 2×202013434241142 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20201343424117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050335856027 + ... + 5050335856030.

Almost surely, 220201343424114 is an apocalyptic number.

20201343424114 is a deficient number, since it is larger than the sum of its proper divisors (10100671712060).

20201343424114 is a wasteful number, since it uses less digits than its factorization.

20201343424114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10100671712059.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 20201343424114 its reverse (41142434310202), we get a palindrome (61343777734316).

The spelling of 20201343424114 in words is "twenty trillion, two hundred one billion, three hundred forty-three million, four hundred twenty-four thousand, one hundred fourteen".

Divisors: 1 2 10100671712057 20201343424114