Base | Representation |
---|---|
bin | 1001001011111011111011… |
… | …11001100001011001110010 |
3 | 2122112020012100122012120211 |
4 | 10211331331321201121302 |
5 | 10121434322404032424 |
6 | 110544211414254334 |
7 | 4153333056625156 |
oct | 445757571413162 |
9 | 78466170565524 |
10 | 20201343424114 |
11 | 64893837956a6 |
12 | 23231a50573aa |
13 | b36c94a33108 |
14 | 4dba70925066 |
15 | 25073b226b94 |
hex | 125f7de61672 |
20201343424114 has 4 divisors (see below), whose sum is σ = 30302015136174. Its totient is φ = 10100671712056.
The previous prime is 20201343424091. The next prime is 20201343424117. The reversal of 20201343424114 is 41142434310202.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 18725810892889 + 1475532531225 = 4327333^2 + 1214715^2 .
It is a super-2 number, since 2×202013434241142 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (20201343424117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050335856027 + ... + 5050335856030.
Almost surely, 220201343424114 is an apocalyptic number.
20201343424114 is a deficient number, since it is larger than the sum of its proper divisors (10100671712060).
20201343424114 is a wasteful number, since it uses less digits than its factorization.
20201343424114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10100671712059.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 20201343424114 its reverse (41142434310202), we get a palindrome (61343777734316).
The spelling of 20201343424114 in words is "twenty trillion, two hundred one billion, three hundred forty-three million, four hundred twenty-four thousand, one hundred fourteen".
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