Base | Representation |
---|---|
bin | 101101111011110001111001… |
… | …100111011010100010011111 |
3 | 222111021221020122210000100221 |
4 | 231323301321213122202133 |
5 | 202434344202230010421 |
6 | 1553354432441102211 |
7 | 60360320645036614 |
oct | 5573617147324237 |
9 | 874257218700327 |
10 | 202020122110111 |
11 | 594082863062a8 |
12 | 1a7a8a2a187967 |
13 | 88955535b3386 |
14 | 37c5b7caa450b |
15 | 18550188a8841 |
hex | b7bc799da89f |
202020122110111 has 4 divisors (see below), whose sum is σ = 202184232689824. Its totient is φ = 201856011530400.
The previous prime is 202020122110061. The next prime is 202020122110117. The reversal of 202020122110111 is 111011221020202.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 202020122110111 - 215 = 202020122077343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (202020122110117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82055288010 + ... + 82055290471.
It is an arithmetic number, because the mean of its divisors is an integer number (50546058172456).
Almost surely, 2202020122110111 is an apocalyptic number.
202020122110111 is a deficient number, since it is larger than the sum of its proper divisors (164110579713).
202020122110111 is a wasteful number, since it uses less digits than its factorization.
202020122110111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164110579712.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 202020122110111 its reverse (111011221020202), we get a palindrome (313031343130313).
The spelling of 202020122110111 in words is "two hundred two trillion, twenty billion, one hundred twenty-two million, one hundred ten thousand, one hundred eleven".
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