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20202201113131 is a prime number
BaseRepresentation
bin1001001011111101100010…
…00001010110001000101011
32122112022102010112022201201
410211332301001112020223
510121443101441110011
6110544432453425031
74153363243102222
oct445766101261053
978468363468651
1020202201113131
1164897839490a4
1223233a433b177
13b370a06340cb
144dbb127c9cb9
1525078b696cc1
hex125fb105622b

20202201113131 has 2 divisors, whose sum is σ = 20202201113132. Its totient is φ = 20202201113130.

The previous prime is 20202201113077. The next prime is 20202201113161. The reversal of 20202201113131 is 13131110220202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20202201113131 - 215 = 20202201080363 is a prime.

It is a super-2 number, since 2×202022011131312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20202201113099 and 20202201113108.

It is not a weakly prime, because it can be changed into another prime (20202201113161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10101100556565 + 10101100556566.

It is an arithmetic number, because the mean of its divisors is an integer number (10101100556566).

Almost surely, 220202201113131 is an apocalyptic number.

20202201113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

20202201113131 is an equidigital number, since it uses as much as digits as its factorization.

20202201113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 20202201113131 its reverse (13131110220202), we get a palindrome (33333311333333).

The spelling of 20202201113131 in words is "twenty trillion, two hundred two billion, two hundred one million, one hundred thirteen thousand, one hundred thirty-one".