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202023213130747 is a prime number
BaseRepresentation
bin101101111011110100110001…
…110110101110001111111011
3222111022020020002002010112201
4231323310301312232033323
5202434422020030140442
61553400103300251031
760360460360215601
oct5573646166561773
9874266202063481
10202023213130747
1159409622094908
121a7a95513a0a77
138895926ab6278
1437c5d93401871
151855149e2b7b7
hexb7bd31dae3fb

202023213130747 has 2 divisors, whose sum is σ = 202023213130748. Its totient is φ = 202023213130746.

The previous prime is 202023213130741. The next prime is 202023213130763. The reversal of 202023213130747 is 747031312320202.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 202023213130747 - 211 = 202023213128699 is a prime.

It is a super-4 number, since 4×2020232131307474 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (202023213130741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101011606565373 + 101011606565374.

It is an arithmetic number, because the mean of its divisors is an integer number (101011606565374).

Almost surely, 2202023213130747 is an apocalyptic number.

202023213130747 is a deficient number, since it is larger than the sum of its proper divisors (1).

202023213130747 is an equidigital number, since it uses as much as digits as its factorization.

202023213130747 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84672, while the sum is 37.

Adding to 202023213130747 its reverse (747031312320202), we get a palindrome (949054525450949).

The spelling of 202023213130747 in words is "two hundred two trillion, twenty-three billion, two hundred thirteen million, one hundred thirty thousand, seven hundred forty-seven".