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2020320213103 = 47311138217159
BaseRepresentation
bin11101011001100100011…
…101111111100001101111
321011010210120220122000101
4131121210131333201233
5231100103433304403
64144042225411531
7265651263315613
oct35314435774157
97133716818011
102020320213103
117098a40aa735
12287675199ba7
131186913961ca
146dad94cb343
1537846deb71d
hex1d66477f86f

2020320213103 has 8 divisors (see below), whose sum is σ = 2069940188160. Its totient is φ = 1970976673080.

The previous prime is 2020320213019. The next prime is 2020320213157. The reversal of 2020320213103 is 3013120230202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2020320213103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2020320213403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69093963 + ... + 69123196.

It is an arithmetic number, because the mean of its divisors is an integer number (258742523520).

Almost surely, 22020320213103 is an apocalyptic number.

2020320213103 is a deficient number, since it is larger than the sum of its proper divisors (49619975057).

2020320213103 is a wasteful number, since it uses less digits than its factorization.

2020320213103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138217517.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 2020320213103 its reverse (3013120230202), we get a palindrome (5033440443305).

The spelling of 2020320213103 in words is "two trillion, twenty billion, three hundred twenty million, two hundred thirteen thousand, one hundred three".

Divisors: 1 47 311 14617 138217159 6496206473 42985536449 2020320213103