20203413402451 has 2 divisors, whose sum is σ = 20203413402452. Its totient is φ = 20203413402450.

The previous prime is 20203413402421. The next prime is 20203413402499. The reversal of 20203413402451 is 15420431430202.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20203413402451 - 2³¹ = 20201265918803 is a prime.

It is a super-3 number, since 3×20203413402451³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20203413402421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10101706701225 + 10101706701226.

It is an arithmetic number, because the mean of its divisors is an integer number (10101706701226).

Almost surely, 2^{20203413402451} is an apocalyptic number.

20203413402451 is a deficient number, since it is larger than the sum of its proper divisors (1).

20203413402451 is an equidigital number, since it uses as much as digits as its factorization.

20203413402451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 20203413402451 its reverse (15420431430202), we get a palindrome (35623844832653).

The spelling of 20203413402451 in words is "twenty trillion, two hundred three billion, four hundred thirteen million, four hundred two thousand, four hundred fifty-one".