Base | Representation |
---|---|
bin | 101101111100000111010011… |
… | …011010001101011011001001 |
3 | 222111101010120021012020202022 |
4 | 231330013103122031123021 |
5 | 202440233233434400231 |
6 | 1553413153110414225 |
7 | 60362063311054313 |
oct | 5574072332153311 |
9 | 874333507166668 |
10 | 202043103434441 |
11 | 59416aa96aa425 |
12 | 1a7b1382661375 |
13 | 8897776833b39 |
14 | 37c6d1ccd07b3 |
15 | 1855911229c7b |
hex | b7c1d368d6c9 |
202043103434441 has 2 divisors, whose sum is σ = 202043103434442. Its totient is φ = 202043103434440.
The previous prime is 202043103434413. The next prime is 202043103434461. The reversal of 202043103434441 is 144434301340202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 144647766841600 + 57395336592841 = 12026960^2 + 7575971^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-202043103434441 is a prime.
It is not a weakly prime, because it can be changed into another prime (202043103434461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101021551717220 + 101021551717221.
It is an arithmetic number, because the mean of its divisors is an integer number (101021551717221).
Almost surely, 2202043103434441 is an apocalyptic number.
It is an amenable number.
202043103434441 is a deficient number, since it is larger than the sum of its proper divisors (1).
202043103434441 is an equidigital number, since it uses as much as digits as its factorization.
202043103434441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 202043103434441 its reverse (144434301340202), we get a palindrome (346477404774643).
The spelling of 202043103434441 in words is "two hundred two trillion, forty-three billion, one hundred three million, four hundred thirty-four thousand, four hundred forty-one".
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