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202103000041 is a prime number
BaseRepresentation
bin1011110000111001000…
…1110000101111101001
3201022122220110011012211
42330032101300233221
511302401332000131
6232502252405121
720413205104315
oct2741621605751
9638586404184
10202103000041
1178790969268
1233203a767a1
131609ac1a6b7
149ad350cb45
1553ccdd05b1
hex2f0e470be9

202103000041 has 2 divisors, whose sum is σ = 202103000042. Its totient is φ = 202103000040.

The previous prime is 202103000023. The next prime is 202103000053. The reversal of 202103000041 is 140000301202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120706910041 + 81396090000 = 347429^2 + 285300^2 .

It is a cyclic number.

It is not a de Polignac number, because 202103000041 - 227 = 201968782313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202102999985 and 202103000030.

It is not a weakly prime, because it can be changed into another prime (202103000081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101051500020 + 101051500021.

It is an arithmetic number, because the mean of its divisors is an integer number (101051500021).

Almost surely, 2202103000041 is an apocalyptic number.

It is an amenable number.

202103000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

202103000041 is an equidigital number, since it uses as much as digits as its factorization.

202103000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 202103000041 its reverse (140000301202), we get a palindrome (342103301243).

The spelling of 202103000041 in words is "two hundred two billion, one hundred three million, forty-one", and thus it is an aban number.