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202112103 = 367370701
BaseRepresentation
bin11000000101111…
…11110001100111
3112002022100200110
430002333301213
5403220041403
632015544103
75002632054
oct1402776147
9462270613
10202112103
11a40a58a6
125782b033
1332b4677b
141cbb202b
1512b25103
hexc0bfc67

202112103 has 4 divisors (see below), whose sum is σ = 269482808. Its totient is φ = 134741400.

The previous prime is 202112089. The next prime is 202112117. The reversal of 202112103 is 301211202.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (202112089) and next prime (202112117).

It is not a de Polignac number, because 202112103 - 24 = 202112087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202112153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33685348 + ... + 33685353.

It is an arithmetic number, because the mean of its divisors is an integer number (67370702).

Almost surely, 2202112103 is an apocalyptic number.

202112103 is a deficient number, since it is larger than the sum of its proper divisors (67370705).

202112103 is an equidigital number, since it uses as much as digits as its factorization.

202112103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67370704.

The product of its (nonzero) digits is 24, while the sum is 12.

The square root of 202112103 is about 14216.6136263176. The cubic root of 202112103 is about 586.8549520837.

Adding to 202112103 its reverse (301211202), we get a palindrome (503323305).

Subtracting 202112103 from its reverse (301211202), we obtain a palindrome (99099099).

The spelling of 202112103 in words is "two hundred two million, one hundred twelve thousand, one hundred three".

Divisors: 1 3 67370701 202112103