Base | Representation |
---|---|
bin | 11101011010011000111… |
… | …101111110010110110011 |
3 | 21011020001222021212011012 |
4 | 131122120331332112303 |
5 | 231103404424342042 |
6 | 4144305452141135 |
7 | 266012150064062 |
oct | 35323075762663 |
9 | 7136058255135 |
10 | 2021201012147 |
11 | 70a206308029 |
12 | 2878801677ab |
13 | 1187a19c9085 |
14 | 6db8048a1d9 |
15 | 378993d3e82 |
hex | 1d698f7e5b3 |
2021201012147 has 2 divisors, whose sum is σ = 2021201012148. Its totient is φ = 2021201012146.
The previous prime is 2021201012099. The next prime is 2021201012153. The reversal of 2021201012147 is 7412101021202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2021201012147 - 28 = 2021201011891 is a prime.
It is not a weakly prime, because it can be changed into another prime (2021201012167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010600506073 + 1010600506074.
It is an arithmetic number, because the mean of its divisors is an integer number (1010600506074).
Almost surely, 22021201012147 is an apocalyptic number.
2021201012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021201012147 is an equidigital number, since it uses as much as digits as its factorization.
2021201012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 2021201012147 its reverse (7412101021202), we get a palindrome (9433302033349).
The spelling of 2021201012147 in words is "two trillion, twenty-one billion, two hundred one million, twelve thousand, one hundred forty-seven".
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