Base | Representation |
---|---|
bin | 10010110100101110… |
… | …101101111111101001 |
3 | 1221011121110202021011 |
4 | 102310232231333221 |
5 | 312343233440311 |
6 | 13141341343521 |
7 | 1313605202446 |
oct | 226456557751 |
9 | 57147422234 |
10 | 20212015081 |
11 | 86321790a5 |
12 | 3b00b67ba1 |
13 | 1ba15aaa4b |
14 | d9a5149cd |
15 | 7d469a321 |
hex | 4b4badfe9 |
20212015081 has 2 divisors, whose sum is σ = 20212015082. Its totient is φ = 20212015080.
The previous prime is 20212015013. The next prime is 20212015121. The reversal of 20212015081 is 18051021202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20135610000 + 76405081 = 141900^2 + 8741^2 .
It is a cyclic number.
It is not a de Polignac number, because 20212015081 - 29 = 20212014569 is a prime.
It is a super-2 number, since 2×202120150812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20212015001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106007540 + 10106007541.
It is an arithmetic number, because the mean of its divisors is an integer number (10106007541).
Almost surely, 220212015081 is an apocalyptic number.
It is an amenable number.
20212015081 is a deficient number, since it is larger than the sum of its proper divisors (1).
20212015081 is an equidigital number, since it uses as much as digits as its factorization.
20212015081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 22.
Adding to 20212015081 its reverse (18051021202), we get a palindrome (38263036283).
It can be divided in two parts, 2021 and 2015081, that added together give a palindrome (2017102).
The spelling of 20212015081 in words is "twenty billion, two hundred twelve million, fifteen thousand, eighty-one".
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