Base | Representation |
---|---|
bin | 10010110100110000… |
… | …001111001011001011 |
3 | 1221011122012222021202 |
4 | 102310300033023023 |
5 | 312343334210011 |
6 | 13141354054415 |
7 | 1313611451111 |
oct | 226460171313 |
9 | 57148188252 |
10 | 20212413131 |
11 | 8632420169 |
12 | 3b0111a40b |
13 | 1ba16b9c91 |
14 | d9a5b9ab1 |
15 | 7d472823b |
hex | 4b4c0f2cb |
20212413131 has 2 divisors, whose sum is σ = 20212413132. Its totient is φ = 20212413130.
The previous prime is 20212413113. The next prime is 20212413139. The reversal of 20212413131 is 13131421202.
Together with previous prime (20212413113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20212413131 - 214 = 20212396747 is a prime.
It is a super-2 number, since 2×202124131312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20212413139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106206565 + 10106206566.
It is an arithmetic number, because the mean of its divisors is an integer number (10106206566).
Almost surely, 220212413131 is an apocalyptic number.
20212413131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20212413131 is an equidigital number, since it uses as much as digits as its factorization.
20212413131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 20212413131 its reverse (13131421202), we get a palindrome (33343834333).
The spelling of 20212413131 in words is "twenty billion, two hundred twelve million, four hundred thirteen thousand, one hundred thirty-one".
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