Base | Representation |
---|---|
bin | 10010110100110011… |
… | …000000101111010001 |
3 | 1221011200120220221212 |
4 | 102310303000233101 |
5 | 312344030443213 |
6 | 13141421425505 |
7 | 1313620600403 |
oct | 226463005721 |
9 | 57150526855 |
10 | 20213140433 |
11 | 8632877642 |
12 | 3b0140b295 |
13 | 1ba18b3035 |
14 | d9a728b73 |
15 | 7d481d9a8 |
hex | 4b4cc0bd1 |
20213140433 has 2 divisors, whose sum is σ = 20213140434. Its totient is φ = 20213140432.
The previous prime is 20213140379. The next prime is 20213140469. The reversal of 20213140433 is 33404131202.
20213140433 is nontrivially palindromic in base 5.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18781880209 + 1431260224 = 137047^2 + 37832^2 .
It is a cyclic number.
It is not a de Polignac number, because 20213140433 - 228 = 19944704977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20213140399 and 20213140408.
It is not a weakly prime, because it can be changed into another prime (20213146433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106570216 + 10106570217.
It is an arithmetic number, because the mean of its divisors is an integer number (10106570217).
Almost surely, 220213140433 is an apocalyptic number.
It is an amenable number.
20213140433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20213140433 is an equidigital number, since it uses as much as digits as its factorization.
20213140433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 20213140433 its reverse (33404131202), we get a palindrome (53617271635).
The spelling of 20213140433 in words is "twenty billion, two hundred thirteen million, one hundred forty thousand, four hundred thirty-three".
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