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2021420151055 = 51492713315639
BaseRepresentation
bin11101011010100110000…
…001111011000100001111
321011020122020122021020001
4131122212001323010033
5231104332024313210
64144343321105131
7266020450533034
oct35324601730417
97136566567201
102021420151055
1170a308a82368
122879216281a7
13118808224876
146dba161138b
15378ad76e03a
hex1d6a607b10f

2021420151055 has 8 divisors (see below), whose sum is σ = 2441984076000. Its totient is φ = 1606282857696.

The previous prime is 2021420150993. The next prime is 2021420151067. The reversal of 2021420151055 is 5501510241202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2021420151055 - 215 = 2021420118287 is a prime.

It is a super-2 number, since 2×20214201510552 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1356657075 + ... + 1356658564.

It is an arithmetic number, because the mean of its divisors is an integer number (305248009500).

Almost surely, 22021420151055 is an apocalyptic number.

2021420151055 is a deficient number, since it is larger than the sum of its proper divisors (420563924945).

2021420151055 is a wasteful number, since it uses less digits than its factorization.

2021420151055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2713315793.

The product of its (nonzero) digits is 4000, while the sum is 28.

Adding to 2021420151055 its reverse (5501510241202), we get a palindrome (7522930392257).

The spelling of 2021420151055 in words is "two trillion, twenty-one billion, four hundred twenty million, one hundred fifty-one thousand, fifty-five".

Divisors: 1 5 149 745 2713315639 13566578195 404284030211 2021420151055