Base | Representation |
---|---|
bin | 11101011010100110000… |
… | …001111011000100011011 |
3 | 21011020122020122021020111 |
4 | 131122212001323010123 |
5 | 231104332024313232 |
6 | 4144343321105151 |
7 | 266020450533052 |
oct | 35324601730433 |
9 | 7136566567214 |
10 | 2021420151067 |
11 | 70a308a82379 |
12 | 2879216281b7 |
13 | 118808224885 |
14 | 6dba1611399 |
15 | 378ad76e047 |
hex | 1d6a607b11b |
2021420151067 has 2 divisors, whose sum is σ = 2021420151068. Its totient is φ = 2021420151066.
The previous prime is 2021420150993. The next prime is 2021420151083. The reversal of 2021420151067 is 7601510241202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2021420151067 - 211 = 2021420149019 is a prime.
It is a super-2 number, since 2×20214201510672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2021420157067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010710075533 + 1010710075534.
It is an arithmetic number, because the mean of its divisors is an integer number (1010710075534).
Almost surely, 22021420151067 is an apocalyptic number.
2021420151067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021420151067 is an equidigital number, since it uses as much as digits as its factorization.
2021420151067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 2021420151067 its reverse (7601510241202), we get a palindrome (9622930392269).
The spelling of 2021420151067 in words is "two trillion, twenty-one billion, four hundred twenty million, one hundred fifty-one thousand, sixty-seven".
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