Base | Representation |
---|---|
bin | 1001001100100000100101… |
… | …10101101110001001110011 |
3 | 2122121002222210112121221101 |
4 | 10212100102311232021303 |
5 | 10122300123124232011 |
6 | 111001224224505231 |
7 | 4154630530626244 |
oct | 446202265561163 |
9 | 78532883477841 |
10 | 20221022102131 |
11 | 64967618a7764 |
12 | 2326b7747b217 |
13 | b38aac985ba6 |
14 | 4dc9ba286ccb |
15 | 250eddb712c1 |
hex | 126412d6e273 |
20221022102131 has 2 divisors, whose sum is σ = 20221022102132. Its totient is φ = 20221022102130.
The previous prime is 20221022102101. The next prime is 20221022102147. The reversal of 20221022102131 is 13120122012202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20221022102131 - 221 = 20221020004979 is a prime.
It is a super-2 number, since 2×202210221021312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20221022102099 and 20221022102108.
It is not a weakly prime, because it can be changed into another prime (20221022102101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110511051065 + 10110511051066.
It is an arithmetic number, because the mean of its divisors is an integer number (10110511051066).
Almost surely, 220221022102131 is an apocalyptic number.
20221022102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20221022102131 is an equidigital number, since it uses as much as digits as its factorization.
20221022102131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 20221022102131 its reverse (13120122012202), we get a palindrome (33341144114333).
The spelling of 20221022102131 in words is "twenty trillion, two hundred twenty-one billion, twenty-two million, one hundred two thousand, one hundred thirty-one".
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