Base | Representation |
---|---|
bin | 11101011011001111101… |
… | …111101000111001111011 |
3 | 21011022110000112100001211 |
4 | 131123033233220321323 |
5 | 231112300210014042 |
6 | 4144541001223551 |
7 | 266044006261231 |
oct | 35331757507173 |
9 | 7138400470054 |
10 | 2022120001147 |
11 | 70a63802a074 |
12 | 287a97a91bb7 |
13 | 1188ba21094c |
14 | 6dc2a54a951 |
15 | 378eee12017 |
hex | 1d6cfbe8e7b |
2022120001147 has 2 divisors, whose sum is σ = 2022120001148. Its totient is φ = 2022120001146.
The previous prime is 2022120001081. The next prime is 2022120001199. The reversal of 2022120001147 is 7411000212202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2022120001147 - 27 = 2022120001019 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022120004147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011060000573 + 1011060000574.
It is an arithmetic number, because the mean of its divisors is an integer number (1011060000574).
Almost surely, 22022120001147 is an apocalyptic number.
2022120001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022120001147 is an equidigital number, since it uses as much as digits as its factorization.
2022120001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 2022120001147 its reverse (7411000212202), we get a palindrome (9433120213349).
The spelling of 2022120001147 in words is "two trillion, twenty-two billion, one hundred twenty million, one thousand, one hundred forty-seven".
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