Base | Representation |
---|---|
bin | 1001001100100010011011… |
… | …11010011101011001011011 |
3 | 2122121012112212110121120111 |
4 | 10212101031322131121123 |
5 | 10122304140334344323 |
6 | 111001510431305151 |
7 | 4154664224052301 |
oct | 446211572353133 |
9 | 78535485417514 |
10 | 20222013199963 |
11 | 64971202a0183 |
12 | 23271b337b1b7 |
13 | b38c0a0c7103 |
14 | 4dca71b58271 |
15 | 25104ab94c0d |
hex | 12644de9d65b |
20222013199963 has 2 divisors, whose sum is σ = 20222013199964. Its totient is φ = 20222013199962.
The previous prime is 20222013199943. The next prime is 20222013200017. The reversal of 20222013199963 is 36999131022202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20222013199963 is a prime.
It is a super-2 number, since 2×202220131999632 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20222013199943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111006599981 + 10111006599982.
It is an arithmetic number, because the mean of its divisors is an integer number (10111006599982).
Almost surely, 220222013199963 is an apocalyptic number.
20222013199963 is a deficient number, since it is larger than the sum of its proper divisors (1).
20222013199963 is an equidigital number, since it uses as much as digits as its factorization.
20222013199963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 49.
The spelling of 20222013199963 in words is "twenty trillion, two hundred twenty-two billion, thirteen million, one hundred ninety-nine thousand, nine hundred sixty-three".
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