Base | Representation |
---|---|
bin | 11101011011011100111… |
… | …111000010000001110001 |
3 | 21011100000111112011022101 |
4 | 131123130333002001301 |
5 | 231113224041440032 |
6 | 4145015014340401 |
7 | 266052344363353 |
oct | 35333477020161 |
9 | 7140014464271 |
10 | 2022342140017 |
11 | 70a741463311 |
12 | 287b3a35a701 |
13 | 118924249a74 |
14 | 6dc4bc530d3 |
15 | 37914690de7 |
hex | 1d6dcfc2071 |
2022342140017 has 2 divisors, whose sum is σ = 2022342140018. Its totient is φ = 2022342140016.
The previous prime is 2022342140003. The next prime is 2022342140041. The reversal of 2022342140017 is 7100412432202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1590484188736 + 431857951281 = 1261144^2 + 657159^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022342140017 - 215 = 2022342107249 is a prime.
It is a super-3 number, since 3×20223421400173 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2022342140047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011171070008 + 1011171070009.
It is an arithmetic number, because the mean of its divisors is an integer number (1011171070009).
Almost surely, 22022342140017 is an apocalyptic number.
It is an amenable number.
2022342140017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022342140017 is an equidigital number, since it uses as much as digits as its factorization.
2022342140017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 2022342140017 its reverse (7100412432202), we get a palindrome (9122754572219).
The spelling of 2022342140017 in words is "two trillion, twenty-two billion, three hundred forty-two million, one hundred forty thousand, seventeen".
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