Base | Representation |
---|---|
bin | 1011110001101010101… |
… | …1001110000001000011 |
3 | 201100012101211122200212 |
4 | 2330122223032001003 |
5 | 11303313104001011 |
6 | 232535042504335 |
7 | 20421312061502 |
oct | 2743253160103 |
9 | 640171748625 |
10 | 202311000131 |
11 | 78888315869 |
12 | 332616650ab |
13 | 16102046186 |
14 | 9b12db4839 |
15 | 53e12ba08b |
hex | 2f1aace043 |
202311000131 has 2 divisors, whose sum is σ = 202311000132. Its totient is φ = 202311000130.
The previous prime is 202311000041. The next prime is 202311000149. The reversal of 202311000131 is 131000113202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202311000131 - 218 = 202310737987 is a prime.
It is a super-2 number, since 2×2023110001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (202311000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101155500065 + 101155500066.
It is an arithmetic number, because the mean of its divisors is an integer number (101155500066).
Almost surely, 2202311000131 is an apocalyptic number.
202311000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
202311000131 is an equidigital number, since it uses as much as digits as its factorization.
202311000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 202311000131 its reverse (131000113202), we get a palindrome (333311113333).
The spelling of 202311000131 in words is "two hundred two billion, three hundred eleven million, one hundred thirty-one", and thus it is an aban number.
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