2023110012113 has 8 divisors (see below), whose sum is σ = 2061312624000. Its totient is φ = 1984908538288.

The previous prime is 2023110012097. The next prime is 2023110012127. The reversal of 2023110012113 is 3112100113202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2023110012113 - 2⁴ = 2023110012097 is a prime.

It is a super-2 number, since 2×2023110012113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2023110012091 and 2023110012100.

It is not an unprimeable number, because it can be changed into a prime (2023110612113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3872408 + ... + 4363686.

It is an arithmetic number, because the mean of its divisors is an integer number (257664078000).

Almost surely, 2^{2023110012113} is an apocalyptic number.

It is an amenable number.

2023110012113 is a deficient number, since it is larger than the sum of its proper divisors (38202611887).

2023110012113 is an equidigital number, since it uses as much as digits as its factorization.

2023110012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 569031.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2023110012113 its reverse (3112100113202), we get a palindrome (5135210125315).

The spelling of 2023110012113 in words is "two trillion, twenty-three billion, one hundred ten million, twelve thousand, one hundred thirteen".