Base | Representation |
---|---|
bin | 1001001100110011100100… |
… | …01010000101010110010011 |
3 | 2122122002021220010221110202 |
4 | 10212121302022011112103 |
5 | 10122432010032211011 |
6 | 111010031244445415 |
7 | 4155441162622415 |
oct | 446316212052623 |
9 | 78562256127422 |
10 | 20231211210131 |
11 | 64a0010335379 |
12 | 2328b3b84986b |
13 | b39a448b5a8c |
14 | 4dd2a55949b5 |
15 | 2513d843623b |
hex | 126672285593 |
20231211210131 has 2 divisors, whose sum is σ = 20231211210132. Its totient is φ = 20231211210130.
The previous prime is 20231211210097. The next prime is 20231211210233. The reversal of 20231211210131 is 13101211213202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20231211210131 is a prime.
It is a super-2 number, since 2×202312112101312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20231211210731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115605605065 + 10115605605066.
It is an arithmetic number, because the mean of its divisors is an integer number (10115605605066).
Almost surely, 220231211210131 is an apocalyptic number.
20231211210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20231211210131 is an equidigital number, since it uses as much as digits as its factorization.
20231211210131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 20231211210131 its reverse (13101211213202), we get a palindrome (33332422423333).
The spelling of 20231211210131 in words is "twenty trillion, two hundred thirty-one billion, two hundred eleven million, two hundred ten thousand, one hundred thirty-one".
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