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202320141 = 367440047
BaseRepresentation
bin11000000111100…
…10100100001101
3112002200221001120
430003302210031
5403243221031
632024231153
75004456432
oct1403624415
9462627046
10202320141
11a4228131
125790b4b9
1332bba37a
141cc27b89
1512b66a96
hexc0f290d

202320141 has 4 divisors (see below), whose sum is σ = 269760192. Its totient is φ = 134880092.

The previous prime is 202320089. The next prime is 202320161. The reversal of 202320141 is 141023202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202320141 - 217 = 202189069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 202320141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202320161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33720021 + ... + 33720026.

It is an arithmetic number, because the mean of its divisors is an integer number (67440048).

Almost surely, 2202320141 is an apocalyptic number.

It is an amenable number.

202320141 is a deficient number, since it is larger than the sum of its proper divisors (67440051).

202320141 is an equidigital number, since it uses as much as digits as its factorization.

202320141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67440050.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 202320141 is about 14223.9284657931. The cubic root of 202320141 is about 587.0562368548.

Adding to 202320141 its reverse (141023202), we get a palindrome (343343343).

The spelling of 202320141 in words is "two hundred two million, three hundred twenty thousand, one hundred forty-one".

Divisors: 1 3 67440047 202320141