Base | Representation |
---|---|
bin | 11101011100010000111… |
… | …010010000010100101001 |
3 | 21011102021012202211101001 |
4 | 131130100322100110221 |
5 | 231122020101144311 |
6 | 4145241254355001 |
7 | 266113053216355 |
oct | 35342072202451 |
9 | 7142235684331 |
10 | 2023213303081 |
11 | 710049189a93 |
12 | 28814205ba61 |
13 | 118a32887979 |
14 | 6dcd1824465 |
15 | 37965dc34c1 |
hex | 1d710e90529 |
2023213303081 has 2 divisors, whose sum is σ = 2023213303082. Its totient is φ = 2023213303080.
The previous prime is 2023213303049. The next prime is 2023213303103. The reversal of 2023213303081 is 1803033123202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2019695745600 + 3517557481 = 1421160^2 + 59309^2 .
It is a cyclic number.
It is not a de Polignac number, because 2023213303081 - 25 = 2023213303049 is a prime.
It is a super-2 number, since 2×20232133030812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2023213303381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011606651540 + 1011606651541.
It is an arithmetic number, because the mean of its divisors is an integer number (1011606651541).
Almost surely, 22023213303081 is an apocalyptic number.
It is an amenable number.
2023213303081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023213303081 is an equidigital number, since it uses as much as digits as its factorization.
2023213303081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 2023213303081 its reverse (1803033123202), we get a palindrome (3826246426283).
The spelling of 2023213303081 in words is "two trillion, twenty-three billion, two hundred thirteen million, three hundred three thousand, eighty-one".
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