Base | Representation |
---|---|
bin | 101110000000011100111110… |
… | …011010110101011110101101 |
3 | 222112102122010201101110120202 |
4 | 232000130332122311132231 |
5 | 203010124340341112140 |
6 | 1554202142050323245 |
7 | 60422446560614663 |
oct | 5600347632653655 |
9 | 875378121343522 |
10 | 202341251504045 |
11 | 595214964a2a35 |
12 | 1a83b10b889525 |
13 | 88b990ca8c734 |
14 | 37d75240bcc33 |
15 | 185d561023915 |
hex | b8073e6b57ad |
202341251504045 has 4 divisors (see below), whose sum is σ = 242809501804860. Its totient is φ = 161873001203232.
The previous prime is 202341251504027. The next prime is 202341251504053. The reversal of 202341251504045 is 540405152143202.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 78489570800356 + 123851680703689 = 8859434^2 + 11128867^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-202341251504045 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20234125150400 + ... + 20234125150409.
It is an arithmetic number, because the mean of its divisors is an integer number (60702375451215).
Almost surely, 2202341251504045 is an apocalyptic number.
It is an amenable number.
202341251504045 is a deficient number, since it is larger than the sum of its proper divisors (40468250300815).
202341251504045 is an equidigital number, since it uses as much as digits as its factorization.
202341251504045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40468250300814.
The product of its (nonzero) digits is 192000, while the sum is 38.
The spelling of 202341251504045 in words is "two hundred two trillion, three hundred forty-one billion, two hundred fifty-one million, five hundred four thousand, forty-five".
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