Base | Representation |
---|---|
bin | 111100010100011… |
… | …1100101001110001 |
3 | 12020001111212012011 |
4 | 1320220330221301 |
5 | 13121121000423 |
6 | 532501202521 |
7 | 101104500652 |
oct | 17050745161 |
9 | 5201455164 |
10 | 2024000113 |
11 | 94954a273 |
12 | 485a00441 |
13 | 26342b405 |
14 | 152b45529 |
15 | bca53b0d |
hex | 78a3ca71 |
2024000113 has 2 divisors, whose sum is σ = 2024000114. Its totient is φ = 2024000112.
The previous prime is 2024000047. The next prime is 2024000141. The reversal of 2024000113 is 3110004202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2017177569 + 6822544 = 44913^2 + 2612^2 .
It is a cyclic number.
It is not a de Polignac number, because 2024000113 - 229 = 1487129201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2024000093 and 2024000102.
It is not a weakly prime, because it can be changed into another prime (2024000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012000056 + 1012000057.
It is an arithmetic number, because the mean of its divisors is an integer number (1012000057).
Almost surely, 22024000113 is an apocalyptic number.
It is an amenable number.
2024000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2024000113 is an equidigital number, since it uses as much as digits as its factorization.
2024000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 2024000113 is about 44988.8887726736. Note that the first 3 decimals coincide. The cubic root of 2024000113 is about 1264.9407322240.
Adding to 2024000113 its reverse (3110004202), we get a palindrome (5134004315).
The spelling of 2024000113 in words is "two billion, twenty-four million, one hundred thirteen", and thus it is an aban number.
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